How to solve the linear equation (b-cx) /(a) + (a-cx) /(b) + 2 = 0? Also, when you divide the equation by the common denominator of the fractions, does it apply to
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How to solve [math] ax^3+bx^2+cx+d=0 [/math] (please simplify if you can) - Quora
![If in the polynomial [math]ax^{3}+bx^{2}+cx+d[/math] a,b,c,d are integers such that ad is odd while bc is even, how do I prove that not all roots of the polynomial are rational? - Quora](https://qph.cf2.quoracdn.net/main-qimg-a9c109bebc314f202f2ad9bd893a8b24.webp "If in the polynomial [math]ax^{3}+bx^{2}+cx+d[/math] a,b,c,d are integers such that ad is odd while bc is even, how do I prove that not all roots of the polynomial are rational? - Quora")
If in the polynomial [math]ax^{3}+bx^{2}+cx+d[/math] a,b,c,d are integers such that ad is odd while bc is even, how do I prove that not all roots of the polynomial are rational? - Quora
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How to make the curve y = ax 4 + bx 3+cx 2 + dx + e have a critical point at (0,3) and have an inflection point at (1,2) with inflectional tangent 6x + y = 8 - Quora
How to make the curve y = ax 4 + bx 3+cx 2 + dx + e have a critical point at (0,3) and have an inflection point at (1,2) with inflectional tangent 6x + y = 8 - Quora
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How to make the curve y = ax 4 + bx 3+cx 2 + dx + e have a critical point at (0,3) and have an inflection point at (1,2) with inflectional tangent 6x + y = 8 - Quora
How to make the curve y = ax 4 + bx 3+cx 2 + dx + e have a critical point at (0,3) and have an inflection point at (1,2) with inflectional tangent 6x + y = 8 - Quora
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How to find the equation of a rational function in the form: y= (ax+b) / (cx+d), where a,b, c,d are integers, with the following characteristics: one vertical asymptote x=2, one horizontal asymptote
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How to find the roots of the algebraic polynomial of the 4-th order x^4+ax ^3+bx^2+cx+d=0 if (c/a) ^2=d - Quora
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What condition must a, b, c and d satisfy for the curve [math]y=ax^4+bx^3+cx ^2+dx+e[/math] to have a point of inflection? - Quora
How to make the curve y = ax 4 + bx 3+cx 2 + dx + e have a critical point at (0,3) and have an inflection point at (1,2) with inflectional tangent 6x + y = 8 - Quora
How to make the curve y = ax 4 + bx 3+cx 2 + dx + e have a critical point at (0,3) and have an inflection point at (1,2) with inflectional tangent 6x + y = 8 - Quora
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